We are asked to solve the Pythagorean equation [tex](6)^2+(8)^2=c^2[/tex] for [tex]c[/tex]. First off, we need to simplify the exponents. When we do so, we get [tex]36+64=c^2 \Rightarrow100=c^2[/tex]. Now, we take the square root of both sides - [tex] \sqrt{100} = \sqrt{c^2} [/tex]. The square and the square root cancel out, giving us [tex]c= \sqrt{100} \Rightarrow \boxed{c=10}[/tex]. Hope this helped!
