Answer:
The spring constant is 222.2 N/m
Explanation:
Given;
mass of the spring, m = 200 g = 0.2 kg
extension of the spring, x = 15 cm = 0.15 m
speed of the mass, v = 5 m/s
spring constant, k = ?
Apply law of conservation of energy;
¹/₂kx² = ¹/₂mv²
k = mv² / x²
k = (0.2 x 5²) / (0.15²)
k = 222.2 N/m
Therefore, the spring constant is 222.2 N/m
