Answer:
= 385.28L
Explanation:
Molecular mass of CO = (12+16) = 28g
Molecular mass of CH3OH = (28+4) = 32g
Molecular mass of H2 = (1+1) = 2g
CO(g) + 2H2(g) ========> CH3OH(l)
moles: 1. 2. 1
1 mole of CO reacts with 2 moles of H2
8.6moles of CO will react with ( 8.6 × 2 )
= 17.2 moles of Hydrogen.
At Standard Temp and Pressure ( s.t.p )
1 mole of H2 occupies 22.4L
17.2 moles of H2 will occupy ( 22.4 × 17.2 )
= 385.28L
