Answer:
[tex]x^2+11x+24 =0[/tex]
Step-by-step explanation:
[tex](x+2)^2+5(x+2)-6=0[/tex]
Substitute
[tex]x+2 =y[/tex]
[tex]y^2+5y-6=0\\(y+6)(y-1)=0\\y=-6,1[/tex]
Now replace y by x values
[tex]x+2=-6\\x=-8\\x+2=-1\\x=-3[/tex]
Roots are -3 and -8
The equivalent equation would be
[tex](x+3)(x+8) =0\\x^2+11x+24 =0[/tex]
