The correct answer is: A) -131
[tex] {b}^{2} - 4ac \: \: where \: b = - 1. \: a = 3. \\ c = 11 \\ { - 1}^{2} - 4(3)(11) = 1 - 4(33) \\ = 1 - 132 = - 131 [/tex]
The discriminant = b2 – 4ac determined from the coefficients of the equation ax2 + bx + c = 0. The discriminant reveals what type of roots the equation has.
Note: b2 – 4ac comes from the quadratic formula.
