Respuesta :

lpearson3
I would first find (a - 2b^2)^2
a^2 - 4ab^2 + 4b^4

Then the problem becomes (a^2 - 4ab^2 + 4b^4)(a^2 - 4ab^2 + 4b^4)

Distribute the first over the second
a^4 - 4a^3b^2 +4ab^4   - 4a^3b^2 +16a^3b^4 - 16ab^6    +4a^2b^4 -16ab^6 + 16b^8
Simplify
a^4 - 8a^3b^2 +4ab^4   +16a^3b^4 - 32ab^6    +4a^2b^4 + 16b^8
rearrange
a^4 - 8a^3b^2 +16a^3b^4 + 4a^2b^4 + 4ab^4  - 32ab^6  + 16b^8

So the fourth term would be 4a^2b^4  (unless I made an error up there!)

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