Just use the following formula:
-----------> sin^2(theta) + cos^2(theta) = 1
So, for " cos(theta) = 6/(√60) " therefore: " cos^2(theta) = [6/(√60)]^2 = 36/60 "
Now. sin^2(theta) + cos^2(theta) = 1
So, sin^2(theta) + 36/60 = 1
So, sin^2(theta) = 1 - 36/60 = 60/60 - 36/60 = 24/60 = 2/5
So, sin^2(theta) = 2/5
Therefore: Either: >>>>> sin(theta) = +√(2/5)
..........................Or: >>>>> sin(theta) = -√(2/5)
Hope I helped. :)
