ayoitsjoanne
ayoitsjoanne
07-07-2014
Mathematics
contestada
I got (x-3)(x^2+9) is it right?
Respuesta :
AL2006
AL2006
07-07-2014
Fantastic ! It's not an easy problem. I'm not even going to go into a
whole big presentation of how to do it. I'll just simply answer the
question you asked:
Yes! Your answer is correct.
Great work !
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konrad509
konrad509
07-07-2014
[tex]\frac{x^5-81x}{x^2+3x}=\\ \frac{x(x^4-81)}{x(x+3)}=\\ \frac{x^4-81}{x+3}=\\ \frac{(x^2-9)(x^2+9)}{x+3}=\\ \frac{(x-3)(x+3)(x^2+9)}{x+3}=\\ (x-3)(x^2+9)[/tex]
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