gracek1 gracek1
  • 09-01-2018
  • Mathematics
contestada

How can we eliminate an imaginary from the denominator? Simplify 2/(3+5i) to demonstrate.

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MANNYCARRILLO6 MANNYCARRILLO6
  • 09-01-2018
Sure multiple by (3-5i)/(3-5i). Keep in mind i^2 is equal to -1. can you do the rest? 

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DankMemes322 DankMemes322
  • 09-01-2018
you can. first multiply both sides of the fraction by (3+5i).
2*(3+5i)/(3+5i)*(3+5i)

(3+5i)*(3+5i)=34

2*(3+5i)/34 divide each side by 2 
(3+5i)/17
[tex] \frac{3}{17} - \frac{5i}{17} [/tex]

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