contestada

A solution contains 0.750 g of mg2 in enough water to make a 1875 ml solution. what is the milliequivalents of mg2 per liter (meq/l) for this solution

Respuesta :

The answer is "32.9 meq/liter".
1875ml = 1875 / 1000 = 1.875ml
mass of magnesium = 24.305 g
0.750 g Mg²+ x 1 mole Mg²⁺/24.305 g x 2 equivalents/mole
= 0.617 equivalents0.0617 eq x 1000 meq/eq = 61.7 meq37.4 meq/1.875 L = 32.9 meq/liter

Otras preguntas

Q&A Platform for Education
Platform Explore for Education