Given: x^2 = ln(xy)
The solution for this problem is:
e^x^2 = xy
y = (e^x^2)/x;
f(x) = (e^x^2);
f'(x) = 2x*(e^x^2);
g(x) = x; g'(x) = 1
[2(x^2)(e^x^2) - (e^x^2)]/x^2 = (e^x^2)(2*(x^2) - 1)/x^2;
plug in x = 1 then this will give us the slope, correct answer which
is e.
