vf = vi + at
vf – vi = at
vi= 0, vf=26 and afor nil = 9.8m/s2
26 = 9.8t
t = 26 / 9.8 = 2.65 s
Now we know the total time, so we can calculate the time 1
second before it hit the ground.
= 2.65 -1 = 1.65s
Now again using the same equation, vf = vi+at, we can find vf
vi = 0, a = 9.8 t=1.65
vf = 0 + 9.8(1.65) =
16.17 m/s
So,
the nail is traveling with the speed of 16.17m/s 1 second before it hits the
ground.
