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A capacitor has plates separated by
8.89 x 10-7 m. To create a
capacitance of 1.11 x 10-9 F, what
must the area of the plates be?
[?] x 10m
Coefficient (green)
Exponent (yellow)

A capacitor has plates separated by 889 x 107 m To create a capacitance of 111 x 109 F what must the area of the plates be x 10m Coefficient green Exponent yell class=

Respuesta :

audreyn06

Answer: 1.115 · 10⁻⁴ m²

Explanation:

The capacitance (C) of a parallel plate capacitor is given by the formula:

C = ε₀A/d, where:

  • ε₀ is the constant for permittivity of free space (8.85 · 10⁻¹² F/m)
  • A is the area of the plates
  • d is the distance between the plates

We are given:

  • C = 1.11 · 10⁻⁹ F
  • d = 8.89 · 10⁻7 m

Let's plug these values into the formula:

1.11 · 10⁻⁹ = (8.85 · 10⁻¹²)(A)/(8.89 · 10⁻7)

Solve for A:

A = 1.115 · 10⁻⁴ m²

The area of the plates must be 1.115 · 10⁻⁴ m².

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