Given:
μ = 3.55 g, population mean
σ = 0.28 g, population standard deviation
n = 17, sample size
80% confidence level
The interval for the mean at the 80% confidence level is
[tex]\mu \pm z^{*} \frac{\sigma}{ \sqrt{n} } [/tex]
From standard tables, obtain z* = 1.28.
Therefore the confidence interval is
3.55 +/- 1.28*(0.28/√17) = 3.55 +/- 0.0869 = (3.463, 3.637)
Answer:
The 80% confidence interval for the average weights of the birds is (3.463, 3.637) g.
That is, 3.463 g < AverageWeight < 3.637 g
