nelsonp33
nelsonp33
08-08-2017
Mathematics
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ANSWER ASAP explain how to solve step by step
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Banabanana
Banabanana
08-08-2017
You can find ∠ACB using the law of cosines:
[tex]cos \angle ACB= \cfrac{AC^2+BC^2-AB^2}{2*AC*BC}= \cfrac{220^2+200^2-160^2}{2*220*200}= \\\\ =\cfrac{48400+40000-25600}{88000}= \cfrac{62800}{88000}= 0.7136 \ \ \to \ m\angle ACB=44.47^o[/tex]
x = 180° - m∠ACB = 180 - 44.47 =
135.53°
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