First, we are going to write it like this:
[tex]\frac{9x^2-25}{3x-5}[/tex]
Then, we are going to do something like factoring, but it's not factoring. An example would be: [tex]x^2-y^2=\left(x+y\right)\left(x-y\right)[/tex]
If we apply it, we would be left with:
[tex]=\frac{\left(3x+5\right)\left(3x-5\right)}{3x-5}[/tex]
We cancel the common factors, and we are left with:
[tex]=3x+5[/tex]
That's our final answer.
Let me know if you need any more help!
Thanks!
-TetraFish
