SavannahThomas87
SavannahThomas87
10-06-2017
Mathematics
contestada
[cos^-1(4/2)-3.14/2]
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mergl
mergl
10-06-2017
cos^-1(4/2)=cos^-1(2)-pi/2
The inverse cosine function has a domain of [-1,1], and -2 is outside of that range, so there is no solution
Unless you meant cos^-1, as in 1/cos or sec, in which case cos(1/2)-pi/2
This would be pi/3-pi/2=-pi/6
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