First step:
Use the Pythagorean theorem to solve for AB (The hypotenuse):
4+4=c^2
c=sqrt(8)
c=2.83
Next solve for the area of the triangle:
A=1/2bh
A=1/2(4)
A=2m^2
Solve for the area of the semicircle:
A=1/2(2[tex] \pi [/tex][tex] r^{2} [/tex])
A=1/2(2(3.14)(1.415)^2)
A=1/2(2(3.14)(2))
A=1/2(12.56)
A=6.28
6.28+2.83=9.11
