bree74
bree74
07-05-2017
Mathematics
contestada
Express in terms of logarithm without exponents
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jdoe0001
jdoe0001
07-05-2017
[tex]\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y) \\ \quad \\ % Logarithm of rationals \\ \quad \\ % Logarithm of exponentials log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\ -----------------------------\\\\ log_b(xy^2z^{-6}\implies log_b(x)+log_b(y^2)+log_b(z^{-6}) \\\\\\log_b(x)+2log_b(y)-6log_b(z)[/tex]
now, the one below that, which is equivalent to that? well, just look above it
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