first, you need to write and balance the reaction equation.
propane C3H8
C3H8 + 5O2 ---> 3CO2 + 4H2O
the use stoichiometry and molar mass to solve
molar mass of propane= 44.1 g/ mol
molar mass of CO2= 44.0 g/ mol
95.6 g C3H8 (1 mol / 44.1 grams) x ( 3 mol CO2/ 1 mol C3H8) x (44.0 grams/ 1 mol CO2)= 286 grams CO2
