nehamishranm198 nehamishranm198

07-05-2017
Mathematics

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If the perimeter of a isosceles right triangle is 2P, then its area is

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FlanScar FlanScar

07-05-2017

Let the length of the isosceles sides be s respectively,
the hypotenuse will be sqrt(2).s
so 2s+sqrt(s).s = 2P
-> s = 2P/(2+sqrt(2))

since its a isosceles right angled triangle, it's area is half of a square with the same side
area = s^2/2 = 2P^2/(2+sqrt(2))^2

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