Respuesta :

Zach456
Well I don't know where inequalities would come in but the third length would be solved as follows.
a^2+b^2=c^2
10^2+18^2=424
[tex] \sqrt{424} [/tex]

Answer;[tex]2 \sqrt{106} [/tex]
I hope this is correct, its what I would do if I had this equation.



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