Answer:
pH = 7.00
Explanation:
In water at 25 °C,
[tex]K_{w} = [\text{H}_{3}\text{O}^{+}][\text{OH}^{-}] = 1.01 \times 10^{-14}\\[/tex]
The solution is neutral, so [tex][\text{H}_{3}\text{O}^{+}] = [\text{OH}^{-}]\\[/tex]
[tex][\text{H}_{3}\text{O}^{+}]^{2} = 1.01 \times 10^{-14}\\[/tex]
[tex][\text{H}_{3}\text{O}^{+}] = \sqrt{1.01 \times 10^{-14}} = 1.00 \times 10^{-7}[/tex]
To get the pH, you take the negative logarithm of the hydronium ion concentration.
[tex]\text{pH} = -\log{( 1.00 \times 10^{-7})} = 7.00\\[/tex]
