5A + 7 = 3A + 7 + 2A
We need to solve for A.
3A + 7 + 2A = 3A + 2A + 7 = 5A + 7 (We can add 3A and 2A because it's the same variable, so we add the coefficients)
5A + 7 = 3A + 7 + 2A
5A + 7 = 5A + 7
5A + 7 is always equal to 5A + 7 because it's the same equation. So the equation got infinitely many solutions.
