Respuesta :

LammettHash
[tex]\tan\left(x+\dfrac\pi2\right)=\dfrac{\sin\left(x+\frac\pi2\right)}{\cos\left(x+\frac\pi2\right)}=\dfrac{\sin x\cos\frac\pi2+\cos x\sin\frac\pi2}{\cos x\cos\frac\pi2-\sin x\sin\frac\pi2}=\dfrac{\cos x}{-\sin x}=-\cot x[/tex]

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