harrydale08
harrydale08
10-02-2015
Mathematics
contestada
P=3a+2b^2 (Make 'a' the subject)
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konrad509
konrad509
10-02-2015
[tex]P=3a+2b^2\\ 3a=P-2b^2\\ a=\dfrac{P-2b^2}{3}[/tex]
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