Answer:
Step-by-step explanation:
[tex]\displaystyle\\ x^8-\frac{1}{81} \\\\x^8-\frac{1}{3^4} =\\\\x^8-(\frac{1}{3})^4 =\\\\x^{4*2}-(\frac{1}{3})^{2*2}= \\\\(x^4)^2-((\frac{1}{3} )^2)^2=\\\\(x^4-(\frac{1}{3})^2)(x^4+(\frac{1}{3} ) ^2)=\\\\(x^{2*2}-(\frac{1}{3})^2)(x^4+\frac{1^2}{3^2} )=\\\\((x^2)^2-(\frac{1}{3})^2)(x^4+\frac{1}{9})=\\\\(x^2-\frac{1}{3} )(x^2+\frac{1}{3})(x^4+\frac{1}{9})[/tex]
