The position at which force is equal to 0 is +1 and -1.
The potential energy of the function is U.
U = 3x + 1 x²
Force is F.
F = 0
[tex]F = \frac{ - dU}{dx}[/tex]
[tex]F= \frac{ - d(3x + 1x ^{2} }{dx} [/tex]
= ( -3 - 3 x²)
= -3 ( 1+ x²)
As the force is zero.
The position at which force is equal to 0 is,
0 = -3 ( 1 + x ²)
[tex]x = \sqrt{ 1} [/tex]
x = 1
Therefore, the position at which force is equal to 0 is +1 and -1.
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