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09-09-2022
Mathematics

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find the HCF of: 6(p² +p-2), 15(p³ + 8) and 18(4p²-p-18)

Respuesta :

09-09-2022

Answer:

Hello,

[tex]answer=\boxed{HCF=3*(p+2)}[/tex]

Step-by-step explanation:

[tex]6(p^2+p-2)=6(p+2)(p-1)\\\\15(p^3+8)=15(p+2)(p^2-2p+4)\\\\18(4p^2-p-18)=18(p+2)(4p-9)\\\\\boxed{HCF=3*(p+2)}[/tex]

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