giselle1398
giselle1398
08-02-2017
Mathematics
contestada
numerical value of cosh(ln5)
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LammettHash
LammettHash
08-02-2017
[tex]\cosh x=\dfrac{e^x+e^{-x}}2[/tex]
So
[tex]\cosh(\ln 5)=\dfrac{e^{\ln5}+e^{-\ln5}}2=\dfrac{5+\frac15}2=\dfrac{13}5[/tex]
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