Answer:
[tex]10^{0.4785+1.468x}=y[/tex]
Step-by-step explanation:
So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: [tex]log(y)=0.4785+1.468x[/tex]. And generally a logarithm can be written in the form [tex]log_ba=c[/tex] which can then be rewritten as [tex]b^c=a[/tex], but since the log has no base, it's assumed to be 10. So in this case you have the equation:
[tex]log_{10}y=0.4785+1.468x[/tex], which can then be written in exponential form as:
[tex]10^{0.4785+1.468x}=y[/tex]
