michaelschiumo100 michaelschiumo100
  • 10-06-2022
  • Mathematics
contestada

prove that 1/sec0-tan0= sec0+tan0

Respuesta :

Medunno13
Medunno13 Medunno13
  • 10-06-2022

Answer:

Step-by-step explanation:

[tex]\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}[/tex]

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