Answer:
-2
Step-by-step explanation:
[tex] {8}^{x + 2} = {32}^{2x + 4} [/tex]
You need to write this in exponential form with the base of 2:
[tex] {2}^{3x + 6} = {2}^{10x + 20} [/tex]
Then you need to set the exponent s equal:
[tex]3x + 6 = 10x + 20[/tex]
Now we just need to solve it. :)
[tex]3x - 10x = 20 - 6[/tex]
[tex] - 7x = 14[/tex]
[tex]x = - 2[/tex]
That's it. :)
