Answer:
A
Step-by-step explanation:
[tex]\frac{2x^2-10x-28}{6x}[/tex] × [tex]\frac{6}{x-7}[/tex] ← factor the quadratic
= [tex]\frac{2(x+2)(x-7)}{6x}[/tex] × [tex]\frac{6}{x-7}[/tex] ← cancel the factor (x - 7) and 6
= [tex]\frac{2(x+2)}{x}[/tex] × 1
= [tex]\frac{2x+4}{x}[/tex]
