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Type the correct answer in the box. Rewrite the quadratic function in the form that best reveals the zeros of the function. f(x)=2(2x2+4x)+3

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evgeniylevi

Try this suggested option:

Step-by-step explanation:

f(x)=2(2x²+4x)+3; ⇔

f(x)=4(x²+2x)+3; ⇔

f(x)=4(x²+2x+1)+3-4; ⇔

f(x)=4(x+1)²-1; ⇔

f(x)=(2x+1)(2x+3).

Then the roots are:

[tex]\left[\begin{array}{ccc}x=-1.5\\x=-0.5\end{array}.[/tex]

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