Answer:
[tex]a=1\\\\b=7[/tex]
Step-by-step explanation:
[tex]\dfrac{x^2 (y^3)^4}{xy^5}\\\\\\=x^{2 -1} \cdot \dfrac{y^{3 \times 4}}{y^5}\\\\\\=x^1 \cdot \dfrac{y^{12}}{y^5}\\\\\\=x^1 \cdot y^{12-5}\\\\\\=x^1 \cdot y^7\\\\\text{Hence a = 1, b = 7}[/tex]
