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1. A 2-kg bowling ball sits on top of a building that is 40 meters tall.

Circle one: KE / GPE / both

Show your work for finding the values of each type of energy the object has:

Respuesta :

Edufirst
1) KE = (1/2)m(v^2) = 0

2) PE = mgh = 2kg * 9.8m/s^2 * 40m = 784 joule
MaxnDav1985

Answer: GPE

Explanation:

GPE = 9.8 x mass x height

GPE = 9.8 x 2kg x 70m = 784 joules

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