Answer:
0.82A
Explanation:
first we resolve the resistors in parallel
i.e 1/R=1/R1+1/R2
=1/R=1/6+1/3
1/R=1/2
R=2/1=2ohms
now we resolve all resistors in series
R=R1+R2+R3
R=6+3+2(the two parallel resistors we resolved are now in series with the others)
R=11ohms
From ohm's law V=IR
I=V/R=9/11= 0.82A.
