[tex]\dfrac{x-2}3 +\dfrac 16 = \dfrac 56 \\\\\implies \dfrac{x-2}3 = \dfrac 56 - \dfrac 16\\\\\implies \dfrac{x-2}3= \dfrac 46\\ \\\implies \dfrac{x-2}3 = \dfrac 23\\\\\implies x -2=2\\\\\implies x =2+2 = 4\\\\\text{Hence, the value of x is 4.}[/tex]
