Answer:
1.5 mol/L
Explanation:
molarity = moles/litres
NaOH = 23 + 16 + 1 = 40 g/mol
[tex] ? \: mol \: naoh \: = 30 \: g \: naoh \: \times \\ \\ \frac{1 \: mol \: naoh}{40 \: g \: naoh} = 0.75 \: mol \: naoh[/tex]
molarity = 0.75 mol NaOH ÷ 0.5 L = 1.5 mol/L NaOH
