nhlamoloinnocent56 nhlamoloinnocent56

10-03-2022
Mathematics

contestada

use co-function and expansion of cos[(90-a)- B] to show that: sin(a+b) = sinacosb +sinbcosa

Respuesta :

algebraic12 algebraic12

10-03-2022

Step-by-step explanation:

[tex] \cos((90 - a) - b) = \cos(90 - a) \cos(b) + \sin(90 - a) \sin(b) [/tex]

[tex] \sin(a) \cos(b) + \cos(a) \sin(b) [/tex]

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