Answer:
[tex]D.\:\left(5x+3\right)\left(3x-4\right)[/tex]
Step-by-step explanation:
[tex]15x^2 - 11x-12[/tex]
[tex]\left(15x^2+9x\right)+\left(-20x-12\right)[/tex]
[tex]15x^2+9x:3x\left(5x+3\right)[/tex]
[tex]-20x-12:-4\left(5x+3\right)[/tex]
[tex]3x\left(5x+3\right)-4\left(5x+3\right)[/tex]
[tex]\left(5x+3\right)\left(3x-4\right)[/tex]
~
