The larger of the triangle’s two acute angles is 65 degrees
Angles in a triangle
Given the expression
sin(x+4) = cos(3x + 2)
Since sin theta = cos(90 - theta), hence;
cos(90 - (x+4)) = cos(3x +2)
cos(86 - x) = cos (3x+2)
Cancel out the cosine functions to have:
86 - x = 3x + 2
-4x = -84
x = 21
Substitute x = 21 into the expression
sin(x+4) = Sin25 =
Hence the larger of the triangle’s two acute angles is 65 degrees
Learn more on acute angles here; https://brainly.com/question/6979153
