The break force of the gondola in the amusement park ride is 50,773.8 N.
Break force of the gondola
The break force of the gondola in the amusement park ride, is calculated by applying Newton's second law of motion as shown below;
F = ma
where;
- m is the total mass = 1,727 kg
- a is acceleration = 3g = 3 x 9.8 m/s² = 29.4 m/s²
F = 1,727 x 29.4
F = 50,773.8 N
Thus, the break force of the gondola in the amusement park ride is 50,773.8 N.
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