Respuesta :

[tex]-2x^{2} +9-2x^{2} -6x+10\\-2x^{2} -2x^{2} -6x+9+10\\-4x^{2} -6x+19[/tex]
Answer:
-c4x^2 - -6x + 19

Explanation
So you add -2x^2 to -2x^2 and you get -4x^s because when you add two negatives they stay negative

Since there is no x’s that aren’t squared you just minus 6x to get -6x

And for the 10 you just add it to 9 and get 19

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