Answer:
17.19%
Explanation:
mass of oxygen = 7.221 - (1.990 + 2.341)
= 2.890g
Empirical formula of the compound
For carbon,
1.990/12 = 0.1658
For hydrogen,
2.341/1 = 2.341
For oxygen,
2.890/16 = 0.1806
0.1658 ÷ 0.1658 = 1
2.341 ÷ 0.1658 = 14.11
0.1806 ÷ 0.1658 = 1.089
Empirical formula of the compound= CH14O
Molar mass= (1×12) + (14×1) + (1×16)
= 12+14+16
= 42g/mol
percentage composition= 7.221/42 × 100
= 17.19%
