seonghwa2005
seonghwa2005 seonghwa2005
  • 09-12-2021
  • Mathematics
contestada

The area of a rectangle is 52 in^2. If the length is 9 inches more than the width, find the
dimensions of the rectangle.

Respuesta :

obinnafavour66
obinnafavour66 obinnafavour66
  • 12-12-2021

Answer:

width=4in.

length=13in

Step-by-step explanation:

let the width of the rectangle be x

then the length will be x+9

Area= length×width

52= (x+9)x

52= x²+9x

x²+9x-52=0

x²+13x-4x-52=0

x(x+13) - 4(x+13)= 0

(x-4)(x+13)=0

x=4 or -13

dimension cannot be negative

hence x=4in

the width is 4in. and the length is 4+9=13in.

Answer Link
sheilacisneros08 sheilacisneros08
  • 28-01-2022

Answer: 52 divided by 9 which equals to 5+7/9 inches

Step-by-step explanation:

Answer Link

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