Answer:
Step-by-step explanation:
Perpendicular lines have negative reciprocal slopes
6x + 5y = 10
5y = -6x + 10
y = (-6/5)x + 2
so a perpendicular line has slope 5/6
y = (5/6)x + b
plug in our desired point
3 = (5/6)6 + b
b = -2
y = (5/6)x - 2
I might be able to help you pass this assignment, but better learn it yourself as I cannot assure you will pass the class.
One of those "Win the battle but lose the war" type situations.
