Respuesta :

bc00014
Let the ?=x
We have
[tex] \frac{64}{81} = \frac{8}{9}^x[/tex]
[tex] \frac{2^6}{3^4}=( \frac{2^3}{3^2} )^x [/tex]=[tex] (\frac{2^3}{3^2})^2=( \frac{2^3}{3^2} )^x [/tex]
2=x
apologiabiology
try and divide
if (8/9)^m=(64/81), then (8/9) must be a factor of 64/81

basically, if x^m=y, then divide y by x untill you get x

divide top by 8 and bottom by 9 to reverse it
we get 8/9
so therefor 8/9 ties 8/9=64/81
therfor the missing exponent is 2

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