CarlaL
CarlaL CarlaL
  • 10-01-2017
  • Chemistry
contestada

9.86 x 10²⁸ O-atoms require what volume (L) N₂O₂ at STP?

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 11-01-2017
First, we use avogadro's number to convert atoms into moles. Then, relate the number of moles from elemental to the compound. Lastly, we use conditions at STP to calculate the volume. We do as follows:

9.86 x 10²⁸ O-atoms ( 1 mol / 6.022x10^23 atoms O) ( 1 mol N2O2 / 2 mol O ) ( 22.4 L / 1 mol ) = 1833809.37 L needed
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